MATH SOLVE

4 months ago

Q:
# the area of a triangular block is 64 sq in. if the base os the triangle is twice the height, how long are the base and the height of the triangle

Accepted Solution

A:

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Define x :

------------------------------------------------------

Let the height be x.

Height = x

Length = 2x

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Solve for x:

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Area of triangle = 1/2 x base x height

64 = 1/2 (x)(2x)

xΒ² = 64

x =Β β64

x = 8

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Find the height and the length:

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Height = x = 8 in

Length = 2x = 2(8) = 16 in

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Answer: The base is 16 in and the height is 8 in.

---------------------------------------------------------------------------

Define x :

------------------------------------------------------

Let the height be x.

Height = x

Length = 2x

------------------------------------------------------

Solve for x:

------------------------------------------------------

Area of triangle = 1/2 x base x height

64 = 1/2 (x)(2x)

xΒ² = 64

x =Β β64

x = 8

------------------------------------------------------

Find the height and the length:

------------------------------------------------------

Height = x = 8 in

Length = 2x = 2(8) = 16 in

---------------------------------------------------------------------------

Answer: The base is 16 in and the height is 8 in.

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